I waste my time because the clients pay me to. ;-)
They get what they want. I told them there would very easy ways around the
filters. but they insisted.....
Thanks!
Tyler Longren
Captain Jack Communications
[EMAIL PROTECTED]
www.captainjack.com
----- Original Message -----
From: "Ryan Fischer" <[EMAIL PROTECTED]>
To: "Tyler Longren" <[EMAIL PROTECTED]>; "php-general"
<[EMAIL PROTECTED]>
Sent: Tuesday, July 24, 2001 2:27 PM
Subject: Re: [PHP] bad word filter
> You wrote:
> > I've been reading the "Profanity Filter" thread in the list archives
> but
> > haven't found anything real helpful. Here's my code so far, this of
> course
> > won't work.
> > <?
> > function filterWords($string, &$result) {
> > $badwords="shit, fuck, ass, bitch";
> > $word=explode(", ", $badwords);
> > for ($i=0; $i<count($word); $i++) {
> > $replace = str_replace("$word[$i]", "****", $string);
> > }
> > }
> > $string = "Ass monkey";
> > filterWords("$string", $result);
> > print "$result";
> > ?>
> >
> > How can I scan for the $badwords in $string and replace $badwords with
> ****?
>
> Why waste your time? People will find a way around the filters anyway,
> if they really want to use the words you're censoring. Just a point to
> be made.
>
> Anyway, here's what I would do:
>
> function filterWords($str){
> $badwords = array("shit", "fuck", "ass", "bitch");
> for($i=0; $i<count($badwords); $i++){
> $str = $eregi_replace("$badwords[$i]", "*****", $str);
> }
> return $str;
> }
> $str = filterWords("Ass monkey");
> print $str; // Prints "***** monkey"
>
> If you want to get really fancy, you can replace the "*****" with some
> function calculating just how many asterisks you need to censor out the
> current word for its length. HTH. :)
>
> --
> -Ryan :: ICQ - 595003 :: GigaBoard - http://www.gigaboard.net/
>
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