On Tue, May 7, 2013 at 8:16 AM, Curtis Maurand <cur...@maurand.com> wrote:
> Hello,
> I'm feeding a filename to a php script on the command line (command line
> program). I run the following against it:
>
> $inputline = fread($inputfile, filesize($argv[1]));
>
> I'm getting an error complaining that the second parameter can't be '0'
The thing to look for, is how did you get $inputfile out of the
command line, and why you'd expect the file name to be in $argv[1] at
that point? Marco's suggestion isn't really going to work as
$inputfile will be a file handle, and filesize() needs the name of the
file. Maybe want to give us a wider look at what your code is doing?
Generically, you can wrap this up as:
function binread_file($filename)
{
$handle = fopen($filename,'rb');
if (FALSE === $handle) die("Unable to open $filename");
$contents = fread($handle, filesize($filename));
if (FALSE === $contents) die("Unable to read $filename");
return $contents;
}
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