Serge,
        That is precisely what I want!  Any ideas on how to accomplish that?

Thanks!
Floyd


On Feb 28, 2013, at 2:52 PM, Serge Fonville <serge.fonvi...@gmail.com> wrote:

> HI,
> 
> It seems like you want something according to the following
> 
> you know your start long/lat
> you can determine the long/lat arround it
> for every of those you determine the route.
> if you follow that route you know the house you find
> otherwise you can use an increasing circle and if it finds an address on the 
> location, you may be able to determine which of the points in the circles 
> (which increase in size) is closest.
> 
> Does that match what you want?
> If not, could you further elaborate what you want exactly?
> 
> Kind regards/met vriendelijke groet,
> 
> Serge Fonville
> 
> http://www.sergefonville.nl
> 
> Convince Microsoft!
> They need to add TRUNCATE PARTITION in SQL Server
> https://connect.microsoft.com/SQLServer/feedback/details/417926/truncate-partition-of-partitioned-table
> 
> 
> 2013/2/28 Floyd Resler <fres...@adex-intl.com>
> 
> 
> 
> On Feb 28, 2013, at 1:04 PM, kenrb...@rbnsn.com wrote:
> 
> > On 28.02.2013 12:36, Floyd Resler wrote:
> >> I have a project where my client would like to find the nearest
> >> street address from where he current is.  Getting the longitude and
> >> latitude is easy enough but I'm having a hard time finding out how to
> >> get the nearest house.  I have found a lot of solutions for addresses
> >> maintained in a database but these addresses won't be in a database.
> >> I thought about just querying Google for each longitude and latitude
> >> within in a small circle but my math skills are nowhere near good
> >> enough to accomplish that.  Anyone have any ideas?
> >>
> >> Thanks!
> >> Floyd
> >
> >
> > Have you tried Google Maps reverse geocoding? 
> > https://developers.google.com/maps/documentation/geocoding/#ReverseGeocoding
> >
> > Ken
> >
> That's what I'm doing but I need to find the closest say five houses to the 
> current latitude and longitude coordinates.
> 
> Thanks!
> Floyd
> 
> 

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