[PHP] fgetcsv doesn't return an array?

[Jay Blanchard]

I thought that fgetcsv returned an array. I can work with it like an 
array but I get the following warning when using it

|Warning:  implode(): Invalid arguments passed on line 155
154     $csvCurrentLine = fgetcsv($csvFile, 4096, ',');
155     $currentLine = implode(",", $csvCurrentLine);
|

Everything that I have read online indicates that it is because 
$csvCurrentLine is not declared as an array. Adding a line to the code

153 |$csvCurrentLine = array();

Does not get rid of the warning. The warning isn't interfering with the 
script working, but it us annoying. Does anyone know the solution?

Thanks!

Jay
|