On 23 Jun 2011 at 14:56, Ethan Rosenberg <eth...@earthlink.net> wrote:
> At 05:21 PM 6/22/2011, you wrote:
>> 2) Instead of doing alert("yippee"), seems to me you should alert on
>> the results of the ajax call. I don't know how you get at those with
>> jquery, but I imagine that is where you'll find the results of doing
>> var_dump($_POST);
> The results should be in $_POST. I have done a print_r and var_dump
> and nothing is there. My question was if the call ever worked.
But you don't know that nothing is there because you haven't looked for the
output.
When an ajax call is made, it causes a script on the server to be run. You tell
the ajax call what script you want to have run, in this case apparently
jq_test.php. All output from that script will be returned to the function you
specify in the ajax call. As I said, I don't know jquery, but I'm guessing that
that is the success: function - and in that you do nothing with the returned
results. I should also point out that *all* output from the script will be
returned there. That means anything from an echo or var_dump statement, but
also anything *outside* <?php and ?>, which means all the html that is in your
file jq_test.php too. It's all concatenated together as one humungous text
string and returned to your ajax success: function. And because you're not
looking at those results, you won't see them.
>> 3) Where *are* you expecting the output from var_dump($_POST); to
>> appear, and why?
> As I understand, $.post [which is an Ajax call??] should put the results into
> $_POST in the URL: in the call.
Well, it might put it into $_POST["move_from"], possibly, but I don't know what
the JavaScript behind this jquery call actually does.
>> 5) For a simple but effective ajax example, see
>> http://www.clothears.org.uk.
> Looks good.
Thanks but have you understood it?
>> 6) If you're attaching an onclick to each table cell, the onclick
>> handler can write the cell's id into the form, seems to me. Why use
>> ajax for that?
> Please tell me how to do that [write cell's id into form].
Something like (e.g.):
Move From: <input type="text" name="move_from" id="xyz"></input>
and then in your onclick handler:
document.getElementById("xyz").textContent = this.id;
I'd say also that you need to keep separate your HTML page (where you display
your 8x8 grid and click on the cells) from any PHP scripts you want to run with
ajax.
--
Cheers -- Tim
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