Yassel,
Do two things:
1. Echo $query, to ensure that it actually is what you think it is
2. Run the query, if you have access, at the mysql console and see what it
returns.
Then you'll know what to fix.
Miles
At 03:37 PM 7/17/01 -0500, Yassel Omar Izquierdo Souchay wrote:
>Hey guys
>here is my code
>
>4: mysql_connect() or die ("Problemas conectandose a la base de datos");
>5: $query="select * from info where FirstName='$FirstName' and
>6: LastName='$LastName' and email='$email'";
>7: $result = mysql_db_query("users", $query);
>*8: $r=mysql_fetch_array($result); ************
>9: $count=$r["count"];
>
>and i follow redcieving this message
>
>Warning: Supplied argument is not a valid MySQL result resource in
>c:\inetpub\wwwroot\PhpAndMysqlTest\test2\reg1.php3 on line 8
>
>
>thanks for your answers
>Yassel
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