I think you want
if (!(${"C_Last_Name$y"})) {
or
if (!(${"C_Last_Name".$y})) {
-----Original Message-----
From: Jeff Oien [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, July 11, 2001 10:22 AM
To: PHP
Subject: RE: [PHP] Variable Next To Variable?
I like this idea but it's giving me a parse error on this code:
if (!{$C_Last_Name}{$y})
I'm looking at the other ideas also.
Jeff Oien
> > if (!$C_Last_Name$y) {
> > The form submitting information to this code has field name like
> > C_Last_Name1 C_Last_Name2 depending on how many Children
> > are signing up for something. So I need $y to represent the number.
>
> You want this:
>
> if (!{$C_Last_Name}{$y}) {
>
> The {} surrounding the variable name tells PHP that those are
> unique entities/variables. For example, you could use the following:
>
> echo "Hello, {$userInfo->printFirstName()}";
>
> to interpolate a class' method call within a string...
>
> Chris
>
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