I think you could use another braket on the second example:
((page== 1 OR page== 3) AND page!= 2) OR ((page== 2 OR page== 3) AND page !=
1)
Other than that I don't think I can help.
How come the page can be 1 or 3, but not 2?
I think you could change the logic, but I don't have enough info about your
code. If page is 1 or 3, it won't be 2 (obviously), but why 2 or 3 is
acceptable?
"Merlin Morgenstern" <merli...@fastmail.fm> wrote in message
news:8e.77.13248.a9edc...@pb1.pair.com...
Hello everybody,
I am having trouble finding a logic for following problem:
Should be true if:
page = 1 OR page = 3, but it should also be true if page = 2 OR page = 3
The result should never contain 1 AND 2 in the same time.
This obviously does not work:
(page = 1 OR page = 3) OR (page = 2 OR page = 3)
This also does not work:
(page = 1 OR page = 3 AND page != 2) OR (page = 2 OR page = 3 AND page !=
1)
Has somebody an idea how to solve this?
Thank you in advance for any help!
Merlin
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