um...I believe your query will return results if there is a match, but your
error message will only display if there is no match. !$result will only be
true if there are no records returned on your query, meaning that the domain
name doesn't exist. From your error message, I'd say that's not what you're
looking for.
--kurt
----- Original Message -----
From: "Richard Kurth" <[EMAIL PROTECTED]>
To: "php" <[EMAIL PROTECTED]>
Sent: Monday, July 09, 2001 10:07 PM
Subject: [PHP] If (!$results) are true what am I missing
> What am I missing hear all I what to do is see if the domaname is
> in the database and if it does print the error message if does not then
> just move on without doing anything
>
>
> $db = MYSQL_CONNECT($roothostname,$rootusername, $rootpassword) OR
DIE("Unable to connect to database");
> mysql_select_db($dbName, $db);
> $result = mysql_query( "SELECT * FROM customers WHERE domaname =
$domain1", $db);
> If (!$result) {
> print_error("<b> This Domain Name $domain1 already exist please
select a new Domain Name </b> ");
> }
>
>
>
>
>
>
>
>
>
>
>
> Best regards,
> Richard
> mailto:[EMAIL PROTECTED]
>
>
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