here may be why:
//Right here you grab a row
$query_data = mysql_fetch_row($result);
//but you don't use it and you move on
while($query_data = mysql_fetch_array($result)) {
----- Original Message -----
From: "Rory O'Connor" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Thursday, July 05, 2001 3:11 PM
Subject: [PHP] Missing first record in PHP/Mysql query
> Excuse me if this is too newbie...but I'm writing a simple script to
> query a database and loop through the reuslts, echoing them on the page.
> When I enter the query at the mysql command line, I get the correct
> results. But the same query run through PHP renders all results except
> the first one. Any idea why? I've included the code snippet below:
>
> //the query to select the data
> $query = "SELECT firstname,email,optin from contact where
> interest='rory'";
> $result = mysql_query($query);
> if(!$result) error_message(sql_error());
>
> $query_data = mysql_fetch_row($result);
>
> while($query_data = mysql_fetch_array($result)) {
> $firstname = $query_data["firstname"];
> $email = $query_data["email"];
> $optin = $query_data["optin"];
>
> echo "<BR>\n";
> echo "$firstname;$email;$optin\n";
>
> } //end while loop
>
> also, what would be the code to output the reuslts to a text file
> instead of (or in addition to) the screen?
>
> thanks,
>
> rory
>
> providing the finest in midget technology
>
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