Boyd, Todd M. wrote:
 > Jesus Christ... everyone on this list must've had a long week, because
> you guys are going blind. :D
> 
> In examples sent to you, people foolishly replaced your $db var with
> $db_connect ONLY FOR PART OF THE SCRIPT. You've defined your database
> connection as $db_connect in some versions of the source, but then you
> reference $db (without _connect) in your mysql_select call in that same
> source.
> 
> $db = mysql_connect([option list here]); # <-- this code instantiates a
> connection
> mysql_select_db([some name], $db); # notice how $db is here?
> $result = mysql_query([some query], $db); # it's here, too!
> 
> $db becomes your resource link when you use mysql_connect. That resource
> link must then be passed to your mysql functions. Otherwise, they have
> no idea which database connection you are attempting to use.
> 
> # BAD:
> $db = mysql_connect([options]);
> $result = mysql_query([some query], $db_connect); # what's $db_connect?
> who knows!
> 
> # GOOD:
> $db = mysql_connect([options]);
> $result = mysql_query([some query], $db); # same resource link from
> mysql_connect
> 
> See?
> 
> HTH,
> 
> 
> // Todd

Yes, and I would also strongly urge (scream at) PJ, to turn on E_ALL
error reporting in any script he has problems with.

#1 you'll figure out the problem because the errors will tell you
exactly what the problem is "undefined variable db_connect", etc...

#2 if you can't figure it out, someone here can easily if you give the
errors.

Virtually every problem you've posted throws an error(s) that will tell
you what the F*** is the problem!

-- 
Thanks!
-Shawn
http://www.spidean.com

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