In Java / C# / C,
$bool &= $anotherBool;
is shorthand for
$bool = $bool & $anotherBool;
So &= forces a reference assignment?
On Tue, Feb 3, 2009 at 12:03 AM, Edmund Hertle
<edmund.her...@student.kit.edu> wrote:
> 2009/2/2 Gavin Hodge <gavin.ho...@gmail.com>
>>
>> Hi,
>>
>> I'm fairly new to PHP, having migrated from the Java / C# world.
>>
>> I wrote some code similar to the following:
>>
>> $success = true;
>> $success &= operation1();
>> $success &= operation2();
>>
>> if ($success === true) {
>> operation3(); // depends on 1 and 2 being successful
>> }
>>
>> This didn't work as expected. After a bit of digging I found:
>> * The &= operation isn't mentioned anywhere in the PHP documentation
>> * The &= function seems to work as expected, however the following is
>> observed...
>> $success = true;
>> $success &= true;
>> print $success == true; // outputs 1
>> print $sucesss === true; // no output
>> * The 'or' assignment operator |= causes no errors but doesn't work.
>>
>> Can any PHP gurus explain why the &= operator works at all, and why
>> === seems to fail afterwards?
>>
>> Cheers,
>> Gavin.
>
> Hey,
> never heard of the "|=" operator. So I think php does not support it.
> I cannot say how "&=" works in Java or C# but as of php it works like that
> (IMO) (reference instead of copy):
> $var1 = "test1";
> $var2 = $var1;
> $var3 &= $var1;
> $var1 = "test2";
> echo var1; // "test2"
> echo var2; // "test1"
> echo var3; // "test2"
>
>
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