> Date: Tue, 2 Dec 2008 19:39:53 -0700> From: [EMAIL PROTECTED]> To: [EMAIL
> PROTECTED]> CC: [EMAIL PROTECTED]; [EMAIL PROTECTED];
> php-general@lists.php.net> Subject: Re: [PHP] How to type arguments> > On
> Tue, Dec 2, 2008 at 1:49 PM, Nathan Rixham <[EMAIL PROTECTED]> wrote:> > >
> Richard Heyes wrote:> >> >> I'm a french student, sorry for my mail :> >>>>
> >>> I want to know how can I type my functions' arguments ?> >>>> >>> It is
> heavy to do :> >>> function post($id)> >>> {> >>> $id=(int)$id;> >>> //...>
> >>>> >>> >> PHP is loosely typed so strictly (...) speaking, that would be
> fine.> >> However, you're best off making sure that what you've been given
> is> >> what you think it is. Ergo, what you've written, is what I would do.>
> >>> >> or tu put (int) before each use...> >>>> >>> >> Not necessary to put
> it there for each use, just the first.> >>> >>> > also worth noting that you
> can type-hint as long as the type you're hinting> > is an object and not a
> primitive:> >> > function post(SomeObject $obj)> > {> > // php will
> effectively throw a catchable fatal error if> > // $obj is not an instance of
> SomeObject> > }> >> > sadly you can't:> >> > function post(int $number)> > {>
> > // doesn't work for primitives> > // but then php has limited primitive
> types :(> > }> > > however, type-hinting does support arrays> > function
> alterArr(array $a) { #.. }> > -nathan
Ok, thank you,
> > type-hint as long as the type you're hinting> > is an object and not a
> > primitive:
yes, but it is heavyer than doint $v=(int)$v;
It is all right
thank you
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