Re: [PHP] Code check please

[Robert Vetter]

Andreas Skarin wrote:
> 
> I've tried to get this working for over an hour
> now, and it still won't. I don't even get an error
> message to help me find the problem so I was
> hoping that someone could check my code for me.
> 
> I'm fooling around with a basic form that is
> supposed to send one's name, surname and e-mail
> address to "receive.php". "receive.php" is then
> supposed to take the information and add it to a
> table called "tabell" in a database called
> "databas", but it doesn't work. I think there
> might be something wrong with my MySQL query.
> 
> - - - - - - - - - - - FORM - - - - - - - - - - - -
> - -
> 
> <form action="receive.php" method="post">
>     <P>F&ouml;rnamn:<br>
>         <input type="text" name="fornamn"
> size="25"></p>
>     <p>Efternamn:<br>
>         <input type="text" name="efternamn"
> size="25"></p>
>     <p>E-mailadress:<br>
>         <input type="text" name="email"
> size="25"></p>
>         <input type="submit" name="submit"
> value="Log in">
> </form>
> 
> - - - - - - - - - - - - - - - - - - - - - - - - -
> - - -
> 
> - - - - - - - - - - - RECEIVE.PHP - - - - - - - -
> - - -
> 
> <?php
> 
> // connection to MySQL
> $connection = mysql_connect("localhost",
> "username", "password");
>     if (!$connection) {
>     echo ("<P>Unable to connect to the database
> server at this time.</P>" );
>     exit();
>     }
> 
> //select database
> if (! @mysql_select_db("databas") ) {
>     echo ("<P>Unable to locate the database at
> this time.</P>");
>     exit();
>     }
> 
> // MySQL query
> $sql = "INSERT INTO tabell SET" .
>         "fornamn ='$fornamn'," .
>         "efternamn='$efternamn'," .
>         "email='$email';";
> ?>

Hello,

and where is the mysql_query($sql) function call?

Robert

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