sorry it needs to be a array for checkbox for the example below. So you
could use is_empty() instead. something like that.
<input type='checkbox' name='something[]' value='1'>
<input type='checkbox' name='something[]' value='2'>
<input type='checkbox' name='something[]' value='3'>
On Tue, Jul 8, 2008 at 7:37 PM, VamVan <[EMAIL PROTECTED]> wrote:
> Hey,
>
> Dude you could use it this way
>
> <input type='checkbox' name='something' value='1'>
> <input type='checkbox' name='something' value='2'>
> <input type='checkbox' name='something' value='3'>
>
> Once u submit it,
>
> do a small server side validation
>
> if(isset($_POST['something'] || $_POST['something']) != ""){
> insert...............
> }
>
> This way you could avoid replacing the values with nulls.
>
> Thanks,
> Vam
>
>
> On Mon, Jul 7, 2008 at 12:25 PM, Jason Pruim <[EMAIL PROTECTED]> wrote:
>
>> Hi everyone!
>>
>> So it's been a nice long weekend, I come in to work and try and mess with
>> a project that I'm working on to get some new features added. All was going
>> well until I realized that now my application is breaking...
>>
>> Here's the details...
>>
>> PHP 5.2
>> MySQL 5.2
>>
>> I store the info in the database which is submitted from a HTML form..
>> Some of it text boxes, some check boxes, some radio buttons... I $_POST the
>> info from the form into the processing script.
>>
>> The problem I'm running into though, is when a value has not changed it
>> doesn't get $_POSTed back and my update script erases the info in the
>> database... I'm trying to avoid using $_GET since it can be quite a few
>> variables.
>>
>> Is there anyway I can do it without comparing the original field to what I
>> am displaying?
>>
>>
>> --
>>
>> Jason Pruim
>> Raoset Inc.
>> Technology Manager
>> MQC Specialist
>> 11287 James St
>> Holland, MI 49424
>> www.raoset.com
>> [EMAIL PROTECTED]
>>
>>
>>
>>
>>
>> --
>> PHP General Mailing List (http://www.php.net/)
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>>
>>
>
