Try:
************************************************
if (!is_array($array_id))
{
$string_id=$array_id;
}
else
{
$string_id= implode(":",$array_id);
}
************************************************
You have to always make sure, you are passing Array into an implode() or
explode().
BTW: your code would look cooler like this:
$string_id = is_array($array_id) ? implode(":",$array_id) : $array_id;
Sincerely,
Maxim Maletsky
Founder, Chief Developer
PHPBeginner.com (Where PHP Begins)
[EMAIL PROTECTED]
www.phpbeginner.com
-----Original Message-----
From: Martin Cabrera Diaubalick [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, May 22, 2001 5:41 PM
To: [EMAIL PROTECTED]
Subject: [PHP] All of a sudden I get Warning: Bad arguments to implode()
in busca_01.php on line 133
Hello Everyone!
This is my code
************************************************
if (count($array_id)==1)
{
$string_id=$array_id;
}
else
{
$string_id= implode(":",$array_id);
}
************************************************
I've been testing it for three days and never had an error, now it comes and
goes. Do you know what could be wrong?
$array_id is an array of integers
Thanks in advance
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