Re: [PHP] Re: outputing image part 2

[Stut]

Ross wrote:
Thanks Stut we are getting somewhere.
Removing the header gives the full binary output of the file in IE and FF. I 
also removes the echos and have the resized image showing in the browser. So 
far so good. I know it works.


Now back to sending the URL.

 I have this

$img_url="http://www.xxxxxxx.co.uk/images/ENbb24469/room1.JPG";;
echo "<img src=\"common/display_image.php?img_url='$img_url'\" width=\"200\" 
height=\"100\" />";


and on the display image page I have:

$img_url= $_GET['img_url'];
$image = imagecreatefromjpeg($img_url);
if ($image === false) { exit; }

/// rest of the resize code goes here.....


This still does not work but if I plug the url in manually at the top of 
display_image.php it works, this suggests it is not being sent properly.

OK, your problem here is the single quotes in the img src around $img_url.

However, I question what you are actually doing. Is the image on the 
same machine as this script? If so you should be using a filename not 
the URL. Also, are you sure you're really saving anything by resizing 
the image on your server like this? You should consider generating the 
smaller version using a cron job and linking to it directly. Resizing 
images on the fly is one of the quickest ways to destroy the scalability 
of a website.

-Stut

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