On 6/13/07, Ross <[EMAIL PROTECTED]> wrote:
Never really used the GD much before very straightforward but how do I output the image on a page. This is fine on a php page on its own but what about one where the headers are already sent?I take it I can do something like this <img scr="get_image.php?url=$img_url"></a>. Anyone got a better method? $image = imagecreatefromjpeg($img_url); if ($image === false) { die ('Unable to open image'); } // Get original width and height echo $width = imagesx($image); echo $height = imagesy($image); // New width and height $new_width = 200; $new_height = 150; // Resample $image_resized = imagecreatetruecolor($new_width, $new_height); imagecopyresampled($image_resized, $image, 0, 0, 0, 0, $new_width, $new_height, $width, $height); // Display resized image header('Content-type: image/jpeg'); imagejpeg($image_resized); die(); -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
Aside from perhaps changing die(); to exit;, though not necessary, I'd say that it looks like you're right on track. Until you find a better way to have HTML display an image than through <IMG SRC=...>, I think it's good to go. -- Daniel P. Brown [office] (570-) 587-7080 Ext. 272 [mobile] (570-) 766-8107 -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
