On 3/24/07, Man-wai Chang <[EMAIL PROTECTED]> wrote:
create table temp ( big5 char(2) ) character set big5 collate big5_bin; insert into temp ( big5 ) values ( 0x9f54 ); insert into temp ( big5 ) values ( 0x9f53 ); The 2nd query will report duplicated key. How should I fix the problem?
What does this has to do with PHP? First of all I don't see any PHP code, and second this is an error in your SQL query, so you should be on the MySQL list. Tijnema
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