On Thu, March 1, 2007 12:56 pm, [EMAIL PROTECTED] wrote: > I tried with /bin/ls but still same thing. I just found out that the > exitcode is -1 but the $stdout actually gives correct answer. But that > doesn't make sense. How can I then control what action to take > depending on the exitcode?
I *think* this could be the result of trying to ls a bunch of files, some of which you don't have permission to 'ls', so you are getting a partial list of stuff, but also an error code for trying to ls stuff you shouldn't have been doing that too, if you see what I mean... I am hoping that your real script is a bit more complicated, as you currently have a shell script that runs PHP only to run a shell script that just does 'ls', which, really, you could probably just splat into your shell script without PHP being involved... -- Some people have a "gift" link here. Know what I want? I want you to buy a CD from some starving artist. http://cdbaby.com/browse/from/lynch Yeah, I get a buck. So? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
