I understand that, but that's what I'm trying to get around doing.
-Justin
-----Original Message-----
From: CC Zona <[EMAIL PROTECTED]>
Sent: Monday, May 07, 2001 1:24 PM
To: [EMAIL PROTECTED]
Subject: Re: [PHP] Variable question
In article
<[EMAIL PROTECTED]>,
[EMAIL PROTECTED] ("King, Justin") wrote:
> A simple eval($mysqldata) isn't going to do it though since the string
> is "Your username is $userdata["username"]"; it'll just spit a parse
> error. I've already tried that
The code being eval'd has to be a valid PHP statement. So if you want
to
echo that string, then "echo" must be part of the eval'd code.
Terminated
with semi-colon, etc.
eval("echo 'Your username is ' . $userdata['username'];");
--
CC
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
To contact the list administrators, e-mail: [EMAIL PROTECTED]
