try,
$photos[] = $buffer; // without $i in brackets, this means append to the end of
the array
in the loop, maybe this helps.
----- Original Message -----
From: "tk" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: 2001. május 7. 19:37
Subject: [PHP] help with fgets
> hi.
>
> i'm trying to read in a text file line by line into an array. i've got
> the following code:
> $i = 0;
> while(!feof ($fp)){
> $buffer = trim(fgets($fp, 4096));
> $photos[i] = $buffer;
> $i++;
> }
> fclose($fp);
>
>
> when i echo $buffer to the screen it prints out hte content of hte file
> line by line
> if i echo $photos[i] to the screen it just prints out random numbers and
> not the content i'd expect
>
> (the code i'm using to do this is:
>
> $i = 0;
> while(!feof ($fp)){
> $buffer = trim(fgets($fp, 4096));
> echo $buffer."<br>";
> $photos[i] = $buffer;
> echo $photos[i]."<br>";
> $i++;
> }
> fclose($fp);
>
> any help would be greatly appreciated
>
> thanks.
>
> todd kennedy
>
>
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