What does "$this->A(); "" do ?(in constructor of class B)
does it make another instance of class A, and if not why do I have to
parse vars to the A constructor ($this->A($var1,$var2))?.
I dont think that is what I want.
A can have many instances of B. B can have many instances of C.
A
B B B
B
CCCC CCCC CCCC CCCC
Should not a instanse(object) of class B bee able to request av var of
the calling object (class A)?
Sorry about this stupid questions, I'm not a coder.
Thomas Munz wrote:
Use 'extends' syntax for sub classes
class A {
var $some_var;
var $class_B;
function A(){
$this->class_B = new B();
$this->some_var=2;
}
}
class B extends A {
var $class_C;
function B(){
$this->A();
$this->class_C = new C();
// $this->some_var= some_var_from_class_A; <-- $this->some_var
contains the value allready
}
}
class C extends A {
function C(){
$this->A();
// $this->some_var= some_var_from_class_A; <-- $this->some_var
contains the value allready
}
}
on Friday 15 September 2006 11:01, Roger Helgesen wrote:
I have 3 classes, CLASS A,B and C
class A {
var $some_var;
var $class_B;
function A(){
$this->class_B = new B();
$this->some_var=2;
}
}
class B {
var $some_var;
var $class_C;
function B(){
$this->class_C = new C();
$this->some_var= some_var_from_class_A;
}
}
class C {
var $some_var;
function C(){
$this->some_var= some_var_from_class_A;
}
}
How can class B and C get the value of $some_var_class_A without using
"$this->class_B = new B($some_var);"
roger helgesen
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