tedd wrote:
Hi gang:

Here's your opportunity to pound me again for not knowing the basics of php.

I vaguely remember something like this being discussed a while back, but can't 
find the reference.

In any event, if one uses --

for ($i="a"; $i<"z"; $i++)
  {
  echo($i);
   }

-- it stops at "y"

But, if you use --

for ($i="a"; $i<="z"; $i++)
  {
  echo($i);
   }

-- it prints considerably more characters after "z" than what one would 
normally expect -- why is that?

Just stopping at "z" would seem to make more sense, wouldn't it? After all, when $i = "z" 
in the first expression, then wouldn't $i be equal to "z" in the second expression and thus halt 
the operation?

What am I missing here?

It's a bit of a quirk. "z"++ is "aa" and "aa" < "z". I would guess this would loop until until just before "za" which would be "yz".

It's a bit like looping through the hexadecimal characters. You would have the same effect. However instead of being base-16 with 0-9-a-f you have base-26 using a-z.

-Rasmus

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