[snip] I've got some code from someone else I've inherited and need to sort out some problems with. The programmer that wrote it originally was much better than I and programmed a little over my head to say the least.
One function that I've come across that has 5 variables as input: function($var1,$var2,!$var2,$var3->cc,$var3->bcc); The question I have is on the 3rd input variable, what does the "!" in front of $var2 do to that variable? [/snip] Hmmm. Looks like a weird mistake, to be sure. If $var2 is boolean it should pass the opposite of its current state. Is $var2 a boolean? It is being passed twice here, once AS and once AS NOT. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
