Hehehe.. Yeah.
Thanks alot, this will do perfectly good.
- Richard
""Plutarck"" <[EMAIL PROTECTED]> wrote in message
9bqhpe$f3d$[EMAIL PROTECTED]">news:9bqhpe$f3d$[EMAIL PROTECTED]...
> If you want to make it easy on yourself, convert it into a timestamp (unix
> preferably). Then all you have to do is:
>
> $dif = time() - $last_access_time;
>
> if ($dif > 3600)
> {
> echo "The user has been inactive for more than an hour.";
> }
>
> That's if you want to make it easy on yourself. If you're a masochist I
> suppose you could play around with mktime() :)
>
>
> --
> Plutarck
> Should be working on something...
> ...but forgot what it was.
>
>
> ""Richard"" <[EMAIL PROTECTED]> wrote in message
> 9bpbf3$fc$[EMAIL PROTECTED]">news:9bpbf3$fc$[EMAIL PROTECTED]...
> > Greetings. (the thread was too far down to be read by anyone)
> >
> > I am having some problems with the code itself! I have done like so,
> > that whenever peopel wishes to see the "onliners", I start a function
> called
> > DelOld(). This will not decrease server speed, nor create conflicts when
> > writing to temporary files and so forth.
> > Now, I tried to gather the following into an exploded array:
> >
> > // the date output
> > $date_output = date("Y-m-d-H-i-A");
> >
> > As you see, I've seperated all with a "-" so I can simply call [0],
> [1],
> > [2],... if I want something. Now, How can I compare if a user is away
for
> > like 10 minutes, or 30 minutes? I have a function called
> > GetLoggDateofUser($Username) which will retreive the $date_output, but
> with
> > colons and spaces, like so:
> > date("Y-m-d H:i A").
> >
> > Do you or anyone else have any suggestions?
> >
> > - Richard
> >
> >
> >
> >
> >
> > --
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> >
>
>
>
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