Here is the working code
You had __constructor() it's __construct()

notice I also moved your saying declaration outside of the constructor.
this is to make it a class level variable.
the way that you had it set it was only in scope until you finished the 
construct code.

I guess I was wrong about the var bit. I do remember having lots of issues 
with it back a few months ago. perhaps theses were fixed in newer versions.
most likely var is depreciated in php5. (can someone confirm this?)

<html>
        <head>
                <title>PHP Class testing</title>
        </head>
        <body>
                <br/>
                <p>This is outside the php code block</p>
                <br/>
                <?php
                        echo "Start defining the class here: <br/>" ;
                        class Test {
                                public $saying = "";

                                function __construct() {
                                        $saying = "Im in the Test Class" ;
                                }
                                function get() {
                                        return $saying ;
                                }
                        }

                        $liveclass = new Test ;
                        echo $liveclass->get() ;
                        echo "<br/>" ;
                        echo "This is in the php code block" ;
                ?>
        </body>
</html>


On Thursday 20 October 2005 09:53 pm, Bob Hartung wrote:
> Changed to:
>    var $saying ;
>    public $saying = "....."
>
> Again, blank page.  Funny though, even the <title>...</title> html block
> is not rendered.  Again, same beavior on 2 FC4 and 1 Win32 install.
>
> Tnx
>
> Bob
>
> Stephen Leaf wrote:
> > Sorry.. 1 more thing.
> > php5 does not use var.
> > use public $variable=value; instead.
> > public is only within a class however. you cannot use it outside.
> >
> > On Thursday 20 October 2005 09:35 pm, Bob Hartung wrote:
> >>Hi all,
> >>   I'm trying to get started in OOP with PHP.  I have the following
> >>short code snipped.  I'f I comment out the 'class Test' definition and
> >>the following references to it, it prints
> >>    This is outside the php code block
> >>
> >>         and
> >>
> >>    Start defining the class here:
> >>
> >>If I do not comment out the code as noted, then the page returned is
> >>totally blank.  It does this with or without using the constructor.
> >>PHP 5 on apache.  Same behavior both on Win32 and FC4.
> >>
> >>All help appreciated to get me going.
> >>
> >>Code Snippet:
> >>
> >><html>
> >>
> >><head>
> >>   <title>PHP Class testing</title>
> >>
> >></head>
> >><body>
> >>    <br>
> >>      <P>This is outside the php code block</P>
> >>    <br>
> >>    <?php
> >>      echo "Start defining the class here: <BR>" ;
> >>/*    class Test
> >>      {
> >>
> >>        function __constructor()
> >>             {
> >>               var $saying ;
> >>                    $saying = "Im in the Test Class" ;
> >>             }
> >>
> >>             function get()
> >>             {
> >>               return $saying ;
> >>
> >>      }
> >>
> >>      var $liveclass ;
> >>      $liveclass = new Test ;
> >>      echo $liveclass->get() ;
> >>      echo "<BR>" ;
> >>      echo "This is in the php code block" ;
> >>*/
> >>    ?>
> >>
> >></body>
> >></html>

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