Hi Jacky
In it's simpliest form try this
###################################
<form action="<?= $PHP_SELF; ?>" method="get">
<input type="checkbox" name="id"><br/>
<input type="submit" name="submit" value="submit">
</form>
<?php
echo (isset($id)) ? "checked" : "not checked";
?>
##################################
>
> Hi all,
> Extremely desparate here as I still cannot get my problem sought
> out, so decided
> to post my question again.
> Allow me to repeat my question again:
> I have a form with the checkbox like this
> <form>
> <?php
> $query="select id from foo";
> $result=($query,$con);
> while ($row = mysql_fetch_array($result))
> {
> print("<input type="checkbox" name="$id" value="on">");
> }
> ....submit button and stuffs here...
> ?>
> </form>
<input type="checkbox" name="$id" value="on">
>
> After I tried check on few checkboxes and submit to next page, at
> next page, how do I check which check box is
> checked so that I can get value of the checked one to process to
> next step?
> I did try isset() and empty() to check if variable exist ( as shown below)
> and did not work as the result always turn up to be "off"
>
> if((empty($id))=='true'){
> echo "off";
> }else{
> echo "on";
> }
>
> And I also try
> if(isset($id))
> {
> ..do echo off here...
> }else{
> ...do echo on....
> }
>
> And the result is always "off" as well.
>
> Somene advice me to use $http_var_gets btu I could not find it
> from manaual,
> is that the solution I need?
> cheers
>
> Jack
> [EMAIL PROTECTED]
> "There is nothing more rewarding than reaching the goal you set
> for yourself"
>
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