Hello Jacky!
Try to echo the variable to see its value.
HTH
----- Original Message -----
From: "Jacky@lilst" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Wednesday, April 18, 2001 10:19 PM
Subject: [PHP] to find out which checkbox is checked
> Hi all,
> I still cannot get my problem sought out, pretty desparate here so decided
> to post my question again.
> Allow me to repeat my question again:
> I have a form with the checkbox like this
> <form>
> <?php
> $query="select id from foo";
> $result=($query,$con);
> while ($row = mysql_fetch_array($result))
> {
> print("<input type="checkbox" name="$id" value="on">");
> }
> ....submit button and stuffs here...
> ?>
> </form>
>
> After I submit to next page, at next page, how do I check which check box
is
> checked?
> I did try isset() and empty() to check if variable exist ( as shown below)
> and did not work as the result always turn up to be "off"
>
> if((empty($id))=='true'){
> echo "off";
> }else{
> echo "on";
> }
>
> And I also try
> if(isset($id))
> {
> ..do echo off here...
> }else{
> ...do echo on....
> }
>
> And the result is always "off" as well.
>
> Somene advice me to use $http_var_gets btu I could not find it from
manaual,
> is that the solution I need?
> cheers
> Jack
> [EMAIL PROTECTED]
> "There is nothing more rewarding than reaching the goal you set for
> yourself"
> ----- Original Message -----
> From: Jacky <[EMAIL PROTECTED]>
> To: Chris Fry <[EMAIL PROTECTED]>
> Cc: <[EMAIL PROTECTED]>
> Sent: Wednesday, April 18, 2001 2:57 PM
> Subject: Re: [PHP] Variable variable
>
>
> > I did look up in the manual for $HTTP_GET_VARS but could not find it?
what
> > is it? a function?
> > sorry to ask this again, just try to find out how to use that.
> > Jack
> > [EMAIL PROTECTED]
> > "There is nothing more rewarding than reaching the goal you set for
> > yourself"
> > ----- Original Message -----
> > From: Chris Fry <[EMAIL PROTECTED]>
> > To: Jacky <[EMAIL PROTECTED]>
> > Cc: <[EMAIL PROTECTED]>
> > Sent: Wednesday, April 18, 2001 2:59 AM
> > Subject: Re: [PHP] Variable variable
> >
> >
> > > Sorry - thought you only had one! - it's late.
> > >
> > > To Name the checkboxes you need:
> > > <?php
> > > while (get records from db) {
> > > $id = id from record;
> > > ?>
> > > <input type="checkbox" name ="<?php print $id; ?>">
> > > <?php
> > > }
> > > ?>
> > >
> > > You would have to do a $HTTP_GET_VARS on the next page to find out
which
> > ones
> > > exist.
> > >
> > > Then your select statement would be:
> > >
> > > $query = "select * from table where id IN ('comma delimited list of
> > values')";
> > >
> > > Messy but do-able!
> > >
> > > Probably a better way - There usually is!
> > >
> > > Chris
> > >
> > > Jacky wrote:
> > >
> > > > so how do I check at the next page which one is checked?
> > > > Jack
> > > > [EMAIL PROTECTED]
> > > > "There is nothing more rewarding than reaching the goal you set for
> > > > yourself"
> > > > ----- Original Message -----
> > > > From: Chris Fry <[EMAIL PROTECTED]>
> > > > To: Jacky <[EMAIL PROTECTED]>
> > > > Cc: <[EMAIL PROTECTED]>
> > > > Sent: Wednesday, April 18, 2001 2:31 AM
> > > > Subject: Re: [PHP] Variable variable
> > > >
> > > > > Jacky,
> > > > >
> > > > > You do not need the value. The variable $id will either exist (if
> the
> > user
> > > > checked it) or not (if the user did not check it).
> > > > >
> > > > > Hope this helps.
> > > > >
> > > > > Chris
> > > > >
> > > > > Jacky wrote:
> > > > >
> > > > > > Hi all
> > > > > > I have a form with check box and name of those checkboxes is
> usuing
> > > > variable lke this,
> > > > > >
> > > > > > <!-- I got the value $id from a table and looping them and
assign
> > them
> > > > to the check box name-->
> > > > > > <input type="checkbox" name ="$id" value="on">
> > > > > >
> > > > > > and when I submit the form to page foo.php4, at that page, I use
> > > > Variable variable to call the value of the check box to see if it
> > checked
> > > > like this
> > > > > >
> > > > > > $quey = "select id from table";
> > > > > > $result = ...... ( assumeing it is done and i got value for $id
> for
> > all
> > > > records from table)
> > > > > >
> > > > > > if ($$id =="on"){
> > > > > > echo "on";
> > > > > > }else{
> > > > > > echo "off";
> > > > > > }
> > > > > >
> > > > > > It always returns echo "off", why is that?
> > > > > > cheers
> > > > > > Jack
> > > > > > [EMAIL PROTECTED]
> > > > > > "There is nothing more rewarding than reaching the goal you set
> for
> > > > yourself"
> > > > >
> > > > > --
> > > > > Chris Fry
> > > > > Quillsoft Pty Ltd
> > > > > Specialists in Secure Internet Services and E-Commerce Solutions
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> > > > > Fax: +61 2 9553 1692
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> > > > >
> > > > > You can download our Public CA Certificate from:-
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> > > > >
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> > > Chris Fry
> > > Quillsoft Pty Ltd
> > > Specialists in Secure Internet Services and E-Commerce Solutions
> > > 10 Gray Street
> > > Kogarah
> > > NSW 2217
> > > Australia
> > >
> > > Phone: +61 2 9553 1691
> > > Fax: +61 2 9553 1692
> > > Mobile: 0419 414 323
> > > eMail: [EMAIL PROTECTED]
> > > http://www.quillsoft.com.au
> > >
> > > You can download our Public CA Certificate from:-
> > > https://ca.secureanywhere.com/htdocs/cacert.crt
> > >
> > > **********************************************************************
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