Did you bother to initialize $table as an array() or are you another
lazy slob of a programmer that expects the engine to read your mind
(cluttered as that may be)?

Cheers,
Rob.

On Thu, 2005-07-14 at 18:33, Fletcher Mattox wrote:
> How does one represent a MySQL table as a two dimensional array
> using the column names as one of the indices?  My naive attempt
> went something like this:
> 
>       while ($row = mysqli_fetch_assoc($result))
>               $table[] = $row;
> 
> but that generated this error;
> 
>       Fatal error: [] operator not supported for strings
> 
> Ok.  So then I try to explicitly assign each row, like this:
> 
>       while ($row = mysqli_fetch_assoc($result))
>               $table[$i++] = $row;
> 
> While that generates no error, $table contains nothing useful when
> I'm done.  So then I try to assign each row and column, like this:
> 
>       while ($row = mysqli_fetch_assoc($result)) {
>               foreach ( $row as $col => $val)
>                       $table[$i][$col] = $val;
>               $i++;
>       }
> 
> And that got me this error:
> 
>       Fatal error: Cannot use string offset as an array 
> 
> So clearly my understanding of PHP arrays is lacking.
> Please help.
> 
> Thanks
> Fletcher
-- 
.------------------------------------------------------------.
| InterJinn Application Framework - http://www.interjinn.com |
:------------------------------------------------------------:
| An application and templating framework for PHP. Boasting  |
| a powerful, scalable system for accessing system services  |
| such as forms, properties, sessions, and caches. InterJinn |
| also provides an extremely flexible architecture for       |
| creating re-usable components quickly and easily.          |
`------------------------------------------------------------'

-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

Reply via email to