Re: [PHP] Extensions: parameters as references

[Yasir Malik]

Is there any list (or forum) that can help me with this?

Thanks,
Yasir

On Fri, 17 Jun 2005, Yasir Malik wrote:

Date: Fri, 17 Jun 2005 11:51:24 -0400 (EDT)
From: Yasir Malik <[EMAIL PROTECTED]>
To: php-general@lists.php.net
Subject: [PHP] Extensions: parameters as references

I am creating a PHP extension. In my function, I want the parameter to be a reference. The extension function works fine only if the variable passed is initialized. For example, here is the extension function:

ZEND_FUNCTION(first_module)
{
  zval *parameter;

  if (zend_parse_parameters(ZEND_NUM_ARGS() TSRMLS_CC,
                            "z", &parameter) == FAILURE)
      return;

  ZVAL_LONG(parameter, 78);
}

When I call this as
<?php
dl("test.so");
$a = 4;
first_module($a);
print "$a\n";
?>

it works fine, but when I call it as:
<?php
dl("test.so");
first_module($a);
print "$a\n";
?>

nothing is outputted. I looked at the source code for various extensions, and I noticed that they called the deconstructor zval_dtor(). I tried this, but it still did not work:

ZEND_FUNCTION(first_module)
{
  zval *parameter;

  if (zend_parse_parameters(ZEND_NUM_ARGS() TSRMLS_CC,
                            "z", &parameter) == FAILURE)
      return;

  zval_dtor(parameter);
  ZVAL_LONG(parameter, 78);
}

Thanks,
Yasir

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