Then this is what I would suggest.

$alph = array('*', 'A', 'B','C'...etc) ;

$i=0;
Echo"<Select name=foo>";
While($alph[$i]){ 
  echo"<option value=$alph[$i]>$alph[$i]";
  $i++; 
}
Echo"</Select>";

On 5/25/05 9:54 PM, "MIGUEL ANTONIO GUIRAO AGUILAR"
<[EMAIL PROTECTED]> wrote:

> Yes, because I will create a <select> field within the for loop, and the
> options of the select should be letters.
> 
> --------------------------
> MIGUEL GUIRAO AGUILERA
> Logistica R8 - Telcel
> Tel: (999) 960.7994
> Cel: 9931-60000
> 
> ----- Mensaje original -----
> De: Stephen Johnson <[EMAIL PROTECTED]>
> Fecha: Miércoles, Mayo 25, 2005 9:49 pm
> Asunto: Re: [PHP-DB] Letters loop
> 
>> 
>> Why? 
>> 
>> If you need to do a loop that runs 26 times just set your high
>> value for 26.
>> 
>> Is there some reason you need to use letters ?
>> 
>> 
>> 
>> On 5/25/05 8:37 PM, "MIGUEL ANTONIO GUIRAO AGUILAR"
>> <[EMAIL PROTECTED]> wrote:
>> 
>>> Hi!!
>>> 
>>> I wanna a do a for loop with letters, Is this possible?
>>> 
>>> for ($i = 'A'; $i <= 'Z'; $i++){
>>> // code
>>> }
>>> 
>>> --------------------------
>>> MIGUEL GUIRAO AGUILERA
>>> Logistica R8 - Telcel
>>> Tel: (999) 960.7994
>>> Cel: 9931-60000
>> 
>> -- 
>> Stephen Johnson
>> The Lone Coder
>> 
>> [EMAIL PROTECTED]
>> http://www.thelonecoder.com
>> 
>> *Continuing the struggle against bad code*
>> --
>> 
>> 
>> 
> 
> 

-- 
Stephen Johnson
The Lone Coder

[EMAIL PROTECTED]
http://www.thelonecoder.com

*Continuing the struggle against bad code*
--

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