I think there maybe a few ways to do this... One is
[EMAIL PROTECTED]@[EMAIL PROTECTED]
That basically says "find me the pattern where one non-at symbol is followed
by an at symbol followed by another non-at symbol"
So if you do
<?php
$string = "@ one more T@@me for @ and i@ the Bl@@dy [EMAIL PROTECTED]";
$pattern = '/[EMAIL PROTECTED](@)[EMAIL PROTECTED]/';
$numMatch = preg_match_all($pattern, $string, $matches);
echo "numMatch: $numMatch\n";
print_r ($matches);
?>
numMatch: 3
Array
(
[0] => Array
(
[0] => @
[1] => i@
[2] => [EMAIL PROTECTED]
)
[1] => Array
(
[0] => @
[1] => @
[2] => @
)
)
Well, where that fails is when you have @'s at the beginning or end of the
string and that's easy enough to do.. So that would mean three searches...
There's probably a way to integrate them into one without loosing integrity,
but it depends on what kind of regexp libs you have, I reckon. It also
depends on what you really are trying to do with this search. Consider
str_replace, strpos and strtr as well.
Thanks,
Carl
-----Original Message-----
From: Al [mailto:[EMAIL PROTECTED]
Sent: Monday, May 16, 2005 3:54 PM
To: php-general@lists.php.net
Subject: regex question
What pattern can I use to match ONLY single occurrences of a character in a
string.
e.g., "Some text @ and some mo@@re and [EMAIL PROTECTED], etc @@@.
I only want the two occurrences with a single occurrence of "@".
@{1} doesn't work; there are 4 matches.
Thanks....
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