> -----Original Message-----
> From: Christopher J. Bottaro [mailto:[EMAIL PROTECTED]
> Sent: Thursday, 12 May 2005 5:13 AM
> To: php-general@lists.php.net
> Subject: [PHP] expand array into function arguments?
>
> You can do this in Python:
>
> <code>
> def myFunc(arg1, arg2, arg):
> #do something
>
> myList = [1, "arg", 5]
> myFunc(*myList) # calls myFunc(1, "arg", 2)
> <code>
>
> Can that be done in PHP, and if so, how?
Don't know if there's a better solution, but at the very least you could put
the values in an array, and pass the array to the function.
$arr = array();
$arr[] = "First";
$arr[] = "Second";
$arr[] = "Third";
$val = my_function($arr);
function my_function($arr_in){
// do something with $arr_in[0];
// do something with $arr_in[1];
// do something with $arr_in[2];
}
Note: if you wanted the function to be able to change the actual values in
the array, you would need to pass it by reference rather than by value, eg:
Function my_function(&$arr_in){ etc...
The ampersand before the variable name in the function declaration indicates
the variable is being passed by reference.
Just a thought.
Much warmth,
Murray
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