hi 

On 5/9/05, Martín Marqués <martin@bugs.unl.edu.ar> wrote:
> I have a text variable that contains "$" symbols, that when I pass it out PHP
> thinks that the "$" mean that a variable name comes right after.

use this

$$text = "$text";


> 
> I tried escaping the "$" put with no luck.
> 
> Is there something I can do?
> 
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>              Universidad Nacional
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