Sorry...
Read morgans topic aswell...
Didnīt see the duplicate mysql_query(). :)
// Tobias
""Tobias Talltorp"" <[EMAIL PROTECTED]> wrote in message
9betpl$nb0$[EMAIL PROTECTED]">news:9betpl$nb0$[EMAIL PROTECTED]...
> > $query=mysql_query("Select pass from members where uname='$username'");
> > $result = mysql_query($query)
> > or die("You are not authorized to be here.");
>
> <?
> $query=mysql_query("Select pass from members where uname='$username'");
> $result = mysql_query($query);
>
> // If the number of rows is less than one (meaning zero) then die()
> if ($mysql_num_rows($result) < 1)) {
> die("You are not authorized to be here.");
> }
> ?>
>
> What you are doing is checking if the query is valid. Your die() would
print
> only if you had a faulty query (try changing pass to pass2), but if the
> username is wrong, it returns an empty set.
> The mysql_query() returns the "resource id #2" that you can use with the
> mysql_fetch_array, mysql_num_rows etc to get printable information.
>
> // Tobias
>
>
>
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