Dan wrote:
>
> This confused me for awhile, because the single equal sign seemed to work
> for comparison, but created inexplicable errors in my programs. It seems
> strange to me that a successful variable value assignment does not return
> true.
>
> example:
>
> <?
>
> $shiny = 1;
> if($shiny = 0){ echo("This wont print"); }
> echo( $shiny ); //this will return 0
>
> ?>
>
> --Dan
>
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Okay...
First:
Checking if $shiny equals 0:
if ($shiny == 0) {
But that's already been discussed.
If you _realy_ want to check if the assignment succeeded:
if (($shiny = 0) == 0) {
Try the following example:
-----
$a = "Hello";
$b = "Wold";
if ($b == $a)
print "Yes, b equals a<BR>\n";
else
print "No, b doesn't equal a<BR>\n";
if (($b = $a) == $a)
print "Yes... now b equals a<BR>\n";
else
print "Oops... b still doesn't equal a!<BR>\n";
-----
Output will be:
No, b doesn't equal a
Yes... now b equals a
--
* R&zE:
***************************
** Renze Munnik
**
** E: [EMAIL PROTECTED]
** M: +31 6 218 111 43
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