Richard Lynch wrote:
[EMAIL PROTECTED] wrote:
...
how odd, i have assumed having a class static you could still throw around
variables inside it, or its only meant to stay in the one static method so
executing it like
As I understand it...
It's not that you can't use any variables at all -- It's that "$this"
doesn't make any sense in that context.
"$this" refers to the particular instance of the object you have created
with "new XYZ"
$xyz = new XYZ();
$xyz->bar();
When bar refers to "$this" it means the same as the "$xyz" instance.
If you are calling a static method XYZ::foo() then, really, there *IS* no
object inside of foo() to be called "$this" -- You didn't create an
instance of XYZ, so there is no instance to be named "$this" -- There is
only the class definition and the method.
It's an object that's not there -- more like the idea of an object without
having an actual concrete object to hang on to.
Hope that helps make sense of it all.
Hell, hope that's actually correct! :-^
its correct. only thing it gets a little more complicated, personally I kind
of got lost in all the internals discussion surround this behaviour...
I just code so that I don't use or accidentally trigger it... in some
cases this means using a protected/private method for an object.
It easiest to see what I'm talking about if you run some code (tested php5):
class XYZ
{
function doit()
{ var_dump( isset($this)); }
}
class ABC {
function doit()
{ var_dump( isset($this)); }
function doMore()
{ XYZ::doit(); $this->doit(); ABC::doit(); }
}
XYZ::doit();echo"--\n";
ABC::doit();echo"--\n";
$x = new XYZ;
$a = new ABC;
$x->doit();echo"--\n";
$a->doit();echo"--\n";
$a->doMore();
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