Hi

Pass the variable as a parameter (without quotes):

<form name="myEditForm" action="edit.phtml?number=<?echo $exedit?>"
method="post" onsubmit="return validate()">

and then in the next page refer to the variable $number, OR

in the next page just refer to the variable $exedit (which gets posted as a
form variable) - This in PHP4

Cheers

Rudolf Visagie
[EMAIL PROTECTED]

-----Original Message-----
From: Curtis [mailto:[EMAIL PROTECTED]]
Sent: 09 April 2001 06:09
To: php
Subject: [PHP] Passing variables,,, I know its not this hard.


Hello,
Could someone please tell me where I am going wrong here.
I have an HTML form and I want to past the input from a text box to the
next page url to connect
to my mysql database.

Here is where I am at now....

<form name="myEditForm" action="edit.phtml?number=<? '$exedit' ?>"
method="post" onsubmit="return validate()">
<input type="text" name="exedit" size="20">
<input type="submit" value="Submit" name="submit">
</form>

the onsubmit is a javascript for validation.

I have tried this every which way, but the correct way.

Could someone point me in the right direction.

Thanks
Curtis



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