"John Nichel" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> web_singer wrote:
> > I am using an array to create a menu and the code to change an image on
> > mouseover.
> > I would also like to change some text on mouseover.  While i can do it
using
> > a swtich in javascript it requires that I hard code all the different
> > options in.  My whole reason for using the php in the first place was to
> > avoid having to hard code anything at all.
> > Does anyone have an idea how I can get the text portion to also use my
> > variable?
> >
> > This is what i have so far...
> > <?
> > $site_pages = array("pageone", "pagetwo", "pagethree" );
> >
> > $site_text = array("this is text one", "this is text two", "this is text
> > three" );
> <snip>
>
> Why not just use a multi-dimensional array?
>
> $site = array (
> 1 => array (
> "page" => "pageone",
> "text" => "this is text one"
> ),
> 2 => array (
> "page" => "pagetwo",
> "text" => "this is text two"
> ),
> so-on, and so-forth...
> )
>
> -- 
> John C. Nichel
> ÜberGeek
> KegWorks.com
> 716.856.9675
> [EMAIL PROTECTED]

Thanks for the response, I am very new to using PHP (really need a newbies
section LOL) and while I can see how a multi-dimensional array would have
been better than using two I am not sure how I would get my code to read
that text in the mouseover.  I can read the two arrays but cannot seem to
tell the code that the variable i am passing in the mouseover is the object
and not the text i want to display.
Hope that you can help :)
WebSinger


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