Many thanks Richard.

I have the table presenting neatly now, thanks for all your help with this
one...!

-- 
-----------------------------
 Michael Mason
 Arras People
 www.arraspeople.co.uk
-----------------------------
"Richard Bewley" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> > I'm only selecting a few fields Richard as I want to try and drop them
> into
> an array and display in a table.
>
> > I know I'm probably going the long way around doing this but I need to
> learn
> from scratch exactly how to do it.
>
> > I appreciate your help and patience very much.
>
> > I've managed to get the query returning some results now. An array. I'm
> going to have to spend a little, well actually quite a bit, of time now
> working out how to present these in a table.
>
> > I assume a for statement will get me pointing in the right direction...?
>
> You are correct that the mysql_fetch_array will return an array which you
> can format into a table.  You can use a while loop if you would like,
which
> is probably the simplest.
>
> <?<php
> $query = mysql_query("SELECT
> ID,Vacancy_Role,Vacancy_Salary,Vacancy_Location,Vacancy_Type FROM
> vacancy_details WHERE Publish='Yes'");
>
> echo "<table cellspacing=\"4\" cellpadding=\"4\" width=\"50%\">\n";
> echo "<tr><td><b>ID:</b></td><td><b>Vacancy Role:</b></td><td><b>Vacancy
> Salary</b></td><td><b>Vacancy Location</b></td><td>Vacancy
> Type</b></td></tr>\n";
>
> while($result = mysql_fetch_array($query)) {
> echo
>
"<tr><td>$result[id]</td><td>$result[Vacancy_Role]</td><td>$result[Vacancy_S
>
alary]</td><td>$result[Vacancy_Location]</td><td>$result[Vacancy_Type]</td><
> /tr>\n";
> }
>
> echo "</table>";
> ?>
>
> -----------------------------------------------------------------
> Thank you,
> Richard Bewley
> [EMAIL PROTECTED]
>
> Equinox Systems and Development
> Website: http://www.eq-dev.com/
>
> Also, please look at our webhosting services, specializing in business web
> hosting starting from $15 per month!

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