thanks "Warren Vail" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > I would recommend you start here; > > http://www.php.net/manual/en/ref.image.php > > As I understand you are trying to understand the process where an image tag > in hmtl causes a browser to request an image be loaded, but because the > image statement looks something like the following; > > <img src="path/to/my/phpscript.php"> > > It causes the browser to request the server to send the phpscript.php file, > and since the server knows that ".php" files are executable, the server then > executes your module. If your module begins by outputting the appropriate > mime headers that indicate the type of image the script will generate, it > then takes the remaining characters sent by the script as the actual image > itself. > > Hope this is what you are looking for. > > Warren Vail > > > -----Original Message----- > From: php [mailto:[EMAIL PROTECTED] > Sent: Thursday, July 15, 2004 5:43 PM > To: [EMAIL PROTECTED] > Subject: Re: [PHP] image > > > like i call an image if the img tag but instead of loading the image it > loads a php script > > "Jason Wong" <[EMAIL PROTECTED]> wrote in message > news:[EMAIL PROTECTED] > > On Friday 16 July 2004 08:06, php wrote: > > > > > how do you catch an image request and instead of the image display > > > php? > > > > Please elaborate. > > > > -- > > Jason Wong -> Gremlins Associates -> www.gremlins.biz > > Open Source Software Systems Integrators > > * Web Design & Hosting * Internet & Intranet Applications Development * > > ------------------------------------------ > > Search the list archives before you post > > http://marc.theaimsgroup.com/?l=php-general > > ------------------------------------------ > > /* > > Neil Armstrong tripped. > > */ > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php
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