>DC> $sunday = strtotime('1 January 1995'); // That day was a Sunday >DC> return strftime("%A", $sunday+(3600*24*$day)); >DC> } > >So despite asking for a way to do it without using dates in functions, >that's exactly what you're doing? > >Heh, gotta love this list sometimes.
No need to be rude - you asked for a way to do it without knowing the specific date. Jan 1 1995 was chosen because the 1st happens to be a sunday, enabling you to take advantage of localized date functions. --------------------------------------------------------------------- michal migurski- contact info and pgp key: sf/ca http://mike.teczno.com/contact.html -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php