Hello Dominique,
Friday, February 20, 2004, 11:29:21 AM, you wrote:
DA> I 've given a value se the code :
DA> $_POST["hiddenField"] = $image_avant;
DA> where $image_avant is a variable which contains a value !!
No, you've overwritten whatever might have been in the $_POST array
with the image_avant value.
Also even if this would work (which it doesn't) you are still
outputting the HTML to the browser BEFORE you do this anyway.
Try like this (as has already been suggested):
<?
print("<form method=\"post\" action=\"image.php\">\n");
print("<input type=\"hidden\" name=\"hiddenField\"
value=\"$image_avant\">\n");
print("<input type=\"submit\" name=\"avant\" value=\"Avant\">\n");
print("</form>\n");
?>
--
Best regards,
Richard Davey
http://www.phpcommunity.org/wiki/296.html
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