Seems to me you need floor($number1 / $number2)
Vincent -----Original Message----- From: Richard Davey [mailto:[EMAIL PROTECTED] Sent: woensdag 11 februari 2004 15:07 To: Jeremy Schroeder Cc: [EMAIL PROTECTED] Subject: Re: [PHP] Math Question Hello Jeremy, Wednesday, February 11, 2004, 2:00:32 PM, you wrote: JS> Is there a function that when you divide 2 numbers you drop the JS> remainder and are left with the whole number. round($number1 / $number2) See the manual for the precision value if you need it. -- Best regards, Richard mailto:[EMAIL PROTECTED] -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
