Sorry, for delayed reply, but anyway thanks for your help and your sugestions to check 
the cron log, after read the tutorial and do some actions (trial and error) for a 
days, finally i found i know it what's going on, the tutorial say that there is two 
way to run php script with cron :
1. First by using cgi ---->> compile the php code into binary file use the path of the 
file
   /usr/bin/php -q /var/www/html/sampel.php, or
2. use lynx http://server.com/sample.php
 
and when i try the step one there is an error like this :

PHP Warning: Unable to load dynamic library '/usr/lib/php4/gd.so' - 
/usr/lib/php4/gd.so: cannot open shared object file: No such file or directory in 
Unknown on line 0

is that somebody know this problem and how to solve it...????

because i fail in the first way, so i use the second way and the script works... and 
the first step still make me confused what's going on...?? does any one have the 
idea....???

Developer <[EMAIL PROTECTED]> wrote:

Could I add a question regarding the cron command?
If you automatically run a php script through the cron command is timeout
taken under account or does it run through the "command line" which is
faster (and timeout is not taken under account?)

Thanks all

Mario

yup, i don't know exacly about your questions but i think your questions is about the 
user account who run the script in the cron, but i use this line to run my  script 
from the cron, is that like this..
*  *  *  *  * lynx http://server.com/sample.php > /dev/null
 
the other tutorial give a sample like this :
1  *  *  *  *  root /usr/bin/php /var/www/html/cron/testcron.php
 
after trial and error i deside to use the first line and works, but i am did'nt check 
the execution time. and i think i got to learn about cron.
 
Thanks for all help.
"linux is mystery so i have to explore" 
idur 
 
 
 
 
 
 
 


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