That shouldnt matter, because FTP_BINARY is a constant, and therfore has a numeric, or string value. The only way FTP_BINARY would become a physical string is if there was quotes around it.
As for the problem, are you sure you have the right connection open, because the error (STOR not understood) sounds like you mat not have connected to a valid FTP server? possibly or permissions? -- Luke "Jay Blanchard" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] [snip] $mode = FTP_BINARY; $picuploadname = $picupload[$i]; $piclocalname = "../pictures/".$piclocal[$i]; ftp_put($conn_ftp,$picuploadname ,$piclocalname ,$mode); [/snip] You cannot put FTP_BINARY into a variable, it then becomes a string instead of a function directive. Cahnge to this and see if it works; ftp_put($conn_ftp,$picuploadname ,$piclocalname , FTP_BINARY); -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
