Hi Marek, I came up with this hack, which seems to work:
$query = "SELECT name, value FROM config WHERE site = '$site' ORDER BY name, seq"; $result = mysql_query($query) or die("Query failed : " . mysql_error()); $conf = array (); $last = ""; while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) { if ($line['name'] == $last) { array_push($conf[$last], $line['value']); } else { $last = $line['name']; $conf[$last] = array ($line['value']); } } mysql_free_result($result); Your's seems more elegant, so I'll give it a try. Thanks, Cameron -----Original Message----- From: Marek Kilimajer [mailto:[EMAIL PROTECTED] Sent: Friday, January 09, 2004 11:06 AM To: Cameron B. Prince Cc: [EMAIL PROTECTED] Subject: Re: [PHP] Dynamically Created Arrays This should be what you need: if(!is_array($conf[$name])) $conf[$name] = array($val); else $conf[$name][] = $val; Cameron B. Prince wrote: > Hey guys, > > I'm making progress on my perl to PHP conversion project but I need some > help... > > I have a configuration table in MySQL made up like this: > > > CREATE TABLE config ( > code mediumint(9) NOT NULL auto_increment, > site varchar(32) NOT NULL default '', > name varchar(64) NOT NULL default '', > value varchar(128) NOT NULL default '', > seq smallint(4) default NULL, > PRIMARY KEY (code) > ) TYPE=MyISAM; > > > It has data like this: > > | 1 | site1 | homedir | /var/www/htdocs/site1 | NULL | > | 2 | site1 | groupname | Group1 | 1 | > | 3 | site1 | groupname | Group2 | 2 | > > > I use this query to get the configuration data: > > SELECT name, value > FROM config > WHERE site = '$site' > ORDER BY name, seq > > > What I want to create is an array of arrays like this: > > $conf[$name][] = $val; > > or > > array_push($conf[$name], $val); > > > So I end up with something like: > > $conf[homedir][0] = /var/www/htdocs/site1 > $conf[groupname][0] = Group1 > $conf[groupname][1] = Group2 > > > > If I were still in Perl-land, I'd use a hash of arrays and push things into > it, but I don't seem to have that option now and I keep getting "Use of > undefined constant name" errors. > > Am I going about this in the right way? Any help would be greatly > appreciated. > > Thanks, > Cameron > !DSPAM:3ffede81271881305314632! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php