On Mon, 2003-12-22 at 12:36, Carey Baird wrote: > Hey, > > I have stored the name of a function as a variable. I have then passed the > variable to another function as follows: > > //put function name in a variable > $contentfunction = ânewsadmincontent()â; > > //pass variable to another function > Html_content($contentfunction); > > //function is: > function html_content($contentfunction) > { > ?> > > <tr> > <td colspan="2" valign="top"> > <table width="100%" height="390" border="1" cellpadding="0" > cellspacing="0" bordercolor="#666666" bgcolor="#FFFFFF"> > <tr> > <td valign="top"> > <? > $contentfunction; //doesnât work > Echo $contentfunction; //outputs the name of the > function but does not evaluate it > Echo â<? â.$contentfunction.â ?>â; //outputs <? > Newsadmincontent() ?> but does not evaluate it > ?> > </td> > </tr> > </table> > </td> > </tr> > > <? > } > > > This does seem like a simple question but I cannot find any information to > help me. Can anyone tell me how to get the function to be executed here?
Try $$contentfunction - Brad -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php