RE: [PHP] how to trap eval error?

[david]

Jay Blanchard wrote:

> [snip]
> eval('$return = $function($input);');
> [/snip]
> 
> The problem is the quotes...the string is not truly being eval'd. Change
> to double quotes
> 
> eval("$return = $function($input);");

thanks for the tip but i am sure you mean:

eval("\$return = \$function(\$input);");

otherwise the variables gets expanded before they get to eval and i end up 
with a syntax error. i found a solution (hopefully) with:

if(function_exists($function)){
        eval('$return = $function($input);');
}else{
        // function does not exists
}

which works quit nicely for now. not sure if that's a good thing to do.

thanks!
david

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